Matematik

(8cos(π)³ - 3cos(π/2)³)·(8cos(π)³ + 3cos(π/2)³) =
(c^-2 + 8b³)² =
(6cos(π)^-2 + c²)² =
(6c^-2 + cos(2π/3)^-1)² =
(7x^-2 + b²)² =
(5b² - c^-2)² =
(5c + 5cos(π/2))·(6c + 3a²) =
(3cos(0) + 5x^-1)·(3cos(0) - 5x^-1) =
(x³ - 6a^-2)² =
(6b² - 6b^-2)·(7a² - 3cos(π/2)^-2) =
(cos(π)^-1 + 3cos(2π/3)³)·(x^-2 + c³) =
(5x^-1 + 7a^-1)² =
(3cos(2π/3)^-1 + 8cos(0)^-2)·(5c² + 5c²) =
(7a^-1 + 6c)² =
(6b² + 8c²)·(5cos(2π/3)³ - 5x^-2) =
(7a^-2 + 6x²)² =
(5cos(2π/3)³ - 3c³)² =
(6c + a^-1)·(cos(0)² - cos(π)^-1) =
(3cos(π)^-2 + 6b^-2)·(3cos(π)^-1 - a³) =
(8a^-2 - cos(π)³)·(8a^-2 + cos(π)³) =
(8b³ + 5c³)·(8b³ - 5c³) =
(7cos(0) - x³)·(8cos(π)³ - 7a^-1) =
(5c² - 7x³)·(7x - 8a^-1) =
(c² + 8cos(π/2)³)·(c² - 8cos(π/2)³) =
(6x^-1 + 7b²)² =