Matematik

(5x^-1 + 6cos(π/2))·(5x^-1 - 6cos(π/2)) =
(8c³ + 6a²)² =
(cos(π)² - c²)·(a³ + 5b³) =
(b^-1 - 7cos(0))·(5b + 7a^-2) =
(3c^-2 + 5cos(2π/3)^-2)² =
(b^-1 - b^-1)·(6b² - 3a³) =
(7b² - 7c)·(7b² + 7c) =
(3c - 7c^-2)·(3c + 7c^-2) =
(3x² + 3c³)·(7b^-2 + a²) =
(5b^-2 - 5x)² =
(cos(2π/3)³ + 5c)·(3a² + 7x³) =
(7b^-2 + 7x²)·(5b² - 6cos(π/2)) =
(8a + 3c³)² =
(8x³ - 5cos(0)²)·(c^-1 + 3cos(π/2)^-1) =
(7a + 5cos(π/2)^-2)·(8c^-2 - b^-1) =
(b - 5a)² =
(cos(π)^-1 + x²)·(cos(π)^-1 - x²) =
(8b^-1 + 8a²)·(3c - 5c^-1) =
(3c - 6c³)² =
(cos(π)^-2 + 5c)·(8c^-2 - 3c²) =
(7x^-1 - 8c^-2)·(7x^-1 + 8c^-2) =
(5x² - 6x³)·(8cos(0)^-1 - 8cos(π)³) =
(5c^-1 + 7x^-2)² =
(5cos(2π/3)² + 3cos(0))² =
(3x³ + 6a^-2)·(3x^-1 - b^-2) =