Matematik

(cos(π/2)² - b²)² =
(8cos(π)³ + 3b²)·(8cos(π)³ - 3b²) =
(6a² - 6c^-1)·(5x² - 6a^-2) =
(c^-1 + 6x^-1)² =
(x³ + 8a²)·(cos(2π/3)² + 7cos(2π/3)³) =
(3cos(π)² + 6x²)·(6c² + 5a³) =
(5cos(2π/3)² - x)² =
(3b³ + 3x)·(7c^-1 + 6c²) =
(3a² + 5a³)·(3a² - 5a³) =
(7a³ + 8cos(2π/3)²)² =
(6cos(π)² - x²)·(6cos(π)² + x²) =
(3a² - 7c³)² =
(6cos(2π/3)^-1 - 7cos(2π/3)³)² =
(5c^-1 - x^-1)·(3b^-2 + 5b) =
(6b³ + 5a^-1)² =
(8c - 7b^-1)·(8c + 7b^-1) =
(8c³ - 7a)·(7x^-1 - 6cos(2π/3)) =
(8c^-2 - 8b³)² =
(c - 5cos(π)²)·(5b^-1 - 6b) =
(8cos(0)² - 6cos(π)^-1)·(5c^-2 - 8cos(π)^-2) =
(cos(π)^-1 + 3b^-1)·(6a^-2 + 3b) =
(5x^-1 - a²)² =
(a^-1 + 8x³)² =
(3cos(0)³ + 7cos(π))·(3cos(0)³ - 7cos(π)) =
(7x² + 8c³)·(5b² - b³) =