Matematik

(8c^-2 - 8c^-1)·(8c^-2 + 8c^-1) =
(3x - 6a²)² =
(3c^-1 + 5cos(π))² =
(3cos(π/2)^-1 - 3cos(π)^-2)·(5x^-1 + 6a³) =
(8a^-1 - 7b)·(3c^-2 + c³) =
(b^-1 + 5cos(0)^-1)² =
(8b³ - 8a)·(3b^-1 - 7b) =
(6cos(π/2)² - 3cos(π/2)^-2)·(3b² + 7x^-2) =
(6c^-2 - 3x³)·(6c^-2 + 3x³) =
(6c² - c)·(6c² + c) =
(3x³ + 6c³)·(3x³ - 6c³) =
(8a³ - 5x²)² =
(7cos(π)^-2 + cos(π/2)²)·(7c² - 8c²) =
(3a^-1 - 5x^-2)² =
(6a² + 5a)·(x^-1 + cos(π)) =
(x² - 5b^-1)² =
(7c³ + 7c^-2)·(8x^-1 + 6b^-1) =
(8b - c^-1)·(6cos(2π/3) - 5a^-2) =
(5a - 8a^-2)·(7c³ + b³) =
(8b^-2 - 6b^-2)·(8b^-2 + 6b^-2) =
(b - 5b^-1)·(5x² + 5cos(0)) =
(8c³ + 8b^-1)·(3a^-2 + x³) =
(3b^-2 - 7cos(π)^-1)·(x - cos(π/2)^-2) =
(x + 8x³)² =
(6b + 3cos(π/2)³)·(3cos(2π/3) + 3cos(0)^-1) =