Matematik

(3c^-2 - 7cos(2π/3)²)·(a + 7c²) =
(cos(π)^-2 - 5c^-1)·(3c³ + 8x) =
(5c³ + 5cos(2π/3)²)·(5c³ - 5cos(2π/3)²) =
(5c + 5b)·(7x² - 8c^-1) =
(3b² - a³)² =
(7b² + 6x)·(7b² - 6x) =
(5a³ - 8cos(π))·(5b - 6cos(0)) =
(7a^-1 - x^-1)·(5cos(0)³ - 8a^-2) =
(x^-1 - cos(2π/3)³)² =
(3b - 6a^-2)·(3b + 6a^-2) =
(7b^-1 - 6x^-2)·(7x^-1 - 8c^-2) =
(5b^-2 + 3cos(0)²)² =
(x - 8b)² =
(8x - 5cos(0)^-1)·(c^-1 - b) =
(3b^-2 + 3b^-1)·(7a^-2 - 6b³) =
(3c - 8a^-2)² =
(3a² + 6a³)·(3c^-2 - 7c³) =
(8cos(0)^-2 - 7b²)·(8cos(0)^-2 + 7b²) =
(5x^-1 - 7x)·(b - 3b²) =
(7b - 5b³)·(5c^-2 + 8b²) =
(3x² - 5a)·(6x³ + c^-1) =
(3a^-1 + cos(2π/3)^-1)² =
(7c² - 5b)·(7c² + 5b) =
(5a³ + 5b²)·(7a³ - 6x³) =
(6a² + 5b²)·(5b³ - 3b²) =