Matematik

(5a³ - 3c^-2)·(a - 5cos(π)^-2) =
(c³ - 3x²)·(8b² + 3cos(0)^-1) =
(8b^-2 + x)·(8cos(2π/3)^-2 - b³) =
(5c^-1 - 8x^-1)·(5c^-1 + 8x^-1) =
(6c³ + 3cos(0))² =
(x^-1 + 8c^-1)·(3x^-2 - 7b^-1) =
(3x - 5cos(π/2)^-2)² =
(8c - 6x^-2)·(5a + 6b^-2) =
(cos(π)^-1 - c²)·(3cos(0)^-1 - 8cos(0)³) =
(5b^-1 - 5cos(π/2)²)·(8cos(π/2)^-2 + c²) =
(7cos(π/2)³ - 5x³)·(5b² + c^-2) =
(3b^-2 - 8b³)·(x³ + 7c) =
(x³ - 5a^-2)·(x³ + 5a^-2) =
(8b² + 8x^-2)·(8a² + 8b^-1) =
(3a^-2 + 7c³)·(x^-2 + 3b^-2) =
(7c² - 3cos(π/2)^-1)·(7c² + 3cos(π/2)^-1) =
(6cos(2π/3) + 6b³)² =
(6cos(π)² - 3c³)·(6b² + 5b^-2) =
(5cos(π) + 6c²)·(5a^-1 - x³) =
(5cos(2π/3)^-1 - 6cos(0)³)·(5cos(0) - b) =
(6x³ + 6a^-2)·(5b^-2 - a^-2) =
(3c^-2 - 8a²)² =
(7x^-2 + 8cos(π)^-1)² =
(6x^-1 - 8b²)·(6x^-1 + 8b²) =
(8b² - 6c^-1)·(8b² + 6c^-1) =