Matematik

(3x^-1 + 8cos(π)^-1)·(6a³ + a^-2) =
(6b² - b²)·(5a² - 7b³) =
(3cos(π/2)³ - 3x³)·(3c³ + 3x²) =
(6c - 5b²)·(6c + 5b²) =
(6x² - 5b³)·(8a^-1 + 3b³) =
(8b + cos(π/2)²)·(8b - cos(π/2)²) =
(6b^-1 + 7c)² =
(b - a)·(7b + a²) =
(3cos(0)^-2 - 7b²)·(7x - c³) =
(8b + 5a)·(b^-1 + 6a²) =
(7a² + 5cos(2π/3)²)·(5x² - 5b³) =
(7c³ - a²)·(3a^-1 + 7x²) =
(7cos(π)³ - 5c³)·(3b - 3c²) =
(7b² + c)·(x² + a³) =
(7cos(2π/3) - 3b)·(7cos(2π/3) + 3b) =
(3b³ + cos(π)^-2)² =
(8a^-1 - a)·(8a^-1 + a) =
(7a² + 8c³)·(7a² - 8c³) =
(8a + 8b^-1)² =
(7cos(π/2)^-2 - 6a^-1)·(6cos(0)^-2 - 7b) =
(3a - 7c^-1)·(3a + 7c^-1) =
(cos(2π/3) - 6c^-2)·(cos(2π/3) + 6c^-2) =
(5a + 3c²)·(5c^-2 - 5b^-1) =
(cos(π)^-2 - 5b³)·(8c^-1 + 5c^-1) =
(3c³ + 5x²)² =