Matematik

(3c^-2 - 6c³)·(3c^-2 + 6c³) =
(c² + 3a^-1)·(c² - 3a^-1) =
(5x² + cos(π/2)²)·(8x³ + 3c^-1) =
(8a³ + 7cos(π)^-1)² =
(8a^-2 + b^-1)·(8a^-2 - b^-1) =
(5a^-1 + 3a^-1)·(5a^-1 - 3a^-1) =
(5cos(π/2)^-1 + 3c³)·(8a^-1 - 5a^-2) =
(c² + 6cos(2π/3)²)·(c² - 6cos(2π/3)²) =
(3b³ - c³)·(3b³ + c³) =
(8cos(π) + 7c^-2)² =
(6b^-2 - 6x²)² =
(x^-2 + 6x²)·(6cos(2π/3)^-2 + 3cos(π)^-2) =
(8b³ + 3b³)·(7c³ + 8cos(π)²) =
(7a^-1 - 7cos(2π/3))² =
(c - 6c³)·(5b - 5c^-1) =
(c² + x^-2)·(a² - 5b²) =
(3cos(0) + a³)·(b + 7a³) =
(x² - 6c³)·(5b^-2 + 8cos(0)³) =
(7x^-2 - 3b)·(3x² + 3cos(2π/3)^-1) =
(6b² + 5b^-2)·(6b² - 5b^-2) =
(8a² + 7b³)·(8a² - 7b³) =
(3b + 5x)·(3cos(π)³ + 7c^-1) =
(cos(π/2)^-2 - 8a)·(3c^-2 + a^-1) =
(5a² + 5x)·(x^-1 + 5c^-2) =
(5x^-1 + 5cos(π)³)·(5a + 5b²) =